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Part III:- Solid Solution and Alloys
We are again going to talk about solid solutions Alloys. In the last lecture, [you can see here Part I:- Solid Solution and Alloys, and Part II:- Solid Solution and Alloys] we said that when you put an impurity in a material, the impurity may go to either Substitutional site or Interstitial site, if it goes to substitutional site makes a substitutional solid solution, and if it go to goes to interstitial site, it makes an Interstitial solid solution and that that where it goes is to determine by the size. So, there are some rules for substitutional solid solutions, which were called as Hume Rothery rules.
So, the examples which we took were Au-Ag, Si-Ge, and Cu-Ni; these are solid solutions. So, if you look at the phase diagram of Si-Ger, this is composition excess % Gefrom 100% Si to 100% Ge. This is the temperature axis. So, Si has a melting point that is nearly 14000C. This is a Ge melting point and what they form is a structure that is throughout the same structure. So, this is let us say it is a Si-Gealloy, which is solid solution.
So, it is a disordered solid solution, and it is not an ordered solid solution. So, at 0% Germanium, it has a structure that is FCC structure. At 100% Germanium, it has a structure that is 100%, which is FCC, and intermediate phases also have intermediate compositions also have FCC structure throughout. It is happening within the same structure, same lattice it is just that some of the sites are being replaced by Ge. If you move from Ge side, some of this Ge atom is going to be replaced by Si. So, even at 50-50, it is 50 Ge, 50 Si with each atom having a probability of being 50% Ge or 50% Si each site occupancy. So, this is a disordered solid solution that shows extended solid solubility. So, this is true for Au-Ag; this is true for Si-Ge; this is true for Cu-Ni.
Similarly, on this side, you will have these boundaries. So, between this and this it will be let say α-phase. Α-phase is a solid solution of B in A. So, it is A with some of the A atoms replaced by B. This is β-phase, this is a solid solution of A in B. Essentially, it means nearly B with some atoms replaced by A and this is a substitutional solid solution which is a disordered substitutional solid solution. Between these two, it gives a mixture of α and β. This is one simple example, there are more complicated examples, where some other phases may form, but this is one simple example of where solid solubility is limited.
Let us say, at this point, it is 10%, it is 5%. It increases as you increase the temperature, typically solid solubility increases as the temperature is increased. So, because the lattice dilates and there are other thermodynamic factors, the competition between entropy and enthalpy eventually determines what the solid solubility will be? But this boundary is the boundary beyond which you cannot add any more B to A. If you add any more B to A, so, up to this point at a fixed temperature, let us say this is room temperature. So, if you keep adding B to A, it will remain in the structure of A up to this point, beyond this point, it will form β-phase.
So, as soon as you cross this point, it will start converting into α+β, and this α+β will continue to remain in existence until you reach this point. The proportion of α and β will change, which will be determined by Lever rule. The proportion of α and β will change in this regime, but you will have two-phase coexistence because the solid solubility of α and β are limited. So, this is the limit of solid solubility of β, this is the limit of solid solubility of α and this happens when you have deviations from Hume Rothery rules, when the size differences are larger, when crystal structures are not similar, when valances are not similar and when electronegativity difference typically gives the information of compound, but these are the factors when you deviate from extensive solid solubility. So, this is what happens in most cases. So, as I said in case of Cu-Zn you can have 35% Zn in Cu. And in the case of Zn, you have 1% Cu in Zn.
So, you can see if, now you can correlate to the previous diagram that on the Cu side, the boundary can extend up to 35%, but on the Zn side, it can extend only up to 1%, and this is because Cu and Zn have different structures, they have different valences. So, that is why when you mix two elements sometimes as I said in Cu-Zn example 50%, you have ordering.
So, in the case of Cu-Zn, what happens is that, so, when you add 35% Zn, it remains as FCC. When you are up to 1%, it remains as HCP. But in between, as I said, it starts forming other phases which are different. So, for example, you had BCC phase in between, or you had a simple, cubic phase in between depending upon the temperature. So, you no longer have FCC, HCP structured phases, you have some other phases. These phases are formed because Cu and Zn tend to form secondary phases. So, especially at lower temperatures, when you mix two elements they tend to arrange in themselves in an ordered fashion. So, this is called as ordering in alloys.
The α-solid solubility is increasing with increase in the. So, at this temperature, if you compare these two temperatures at T1 and T2, at T2, α has more amount of B than at T1. Similarly, at T2 β-has, more amount of A, but you can see AxBy, remains vertical. The composition of AxBy does not change, it is a line compound. When you are some other composition, you have α+AxBy, but composition of AxBy will remain same. For example, at this temperature, if you keep the composition fixed, again you have α+AxBy, but composition of α has changed according to this composition. So, at this temperature, α had a composition of C1, at this composition, α-has a composition of C2, but AxBy has same composition throughout. This is a line compound, which means it has a fixed composition, and it forms at only at that particular composition.
So, in two particulars, you will see a composition. You will have two phases, one of may one of them may be a line compound, for example, Cementite, in Steel. Cementite is a fixed composition. So, in Steel, that is a very good example.
So, Fe3C as you change the temperature. So, if I am at let us say 0.5% carbon- steel at temperature T1 and a temperature T2, I have α and Fe3C in both cases, but here α has a different composition, this is number 1, this is number 2, but Fe3C has the same composition, which is determined by this vertical line, which is Fe3C. It is a line compound. So, this is the line compound or an intermetallic compound.
Similarly, cementite in steel is extremely hard. That is why we prefer high carbon steels for application requires high hardness, and this high hardness comes from cementite. And similarly, Cu3Au. These precipitates form in Cu-Au systems, and they again give rise to high hardness. Similarly there are a lot of other systems, like Cu-Al, Cu-Zn. So, all of these Intermetallics of fixed composition have high hardness.
Finally, to calculate the theoretical density of a material, it is given as,
Where, n = number of atoms per unit cell, A is atomic weight, Vc is the volume of unit cell, NA is the Avogadro number.
For the Previous Lecture Click below
Part II:- Solid Solution and AlloysThank you very much
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